展开 2t(t^2-sin(x)+1)

解答

展开

2 t (t^{2} - sin (x) + 1)

2 t^{3} - 2 t sin (x) + 2 t

求解步骤

2 t (t^{2} - sin (x) + 1)

使用分配律:

m (a + b + c) = ma + mb + m c

2 t (t^{2} - sin (x) + 1) = 2 t t^{2} + 2 t (- sin (x)) + 2 t \cdot 1

= 2 t t^{2} + 2 t (- sin (x)) + 2 t \cdot 1

化简

2 t t^{2} + 2 t (- sin (x)) + 2 t \cdot 1 : 2 t^{3} - 2 t sin (x) + 2 t

= 2 t^{3} - 2 t sin (x) + 2 t

s im pl i f y (x - \frac{1}{2}) \cdot (x + \frac{1}{2})

s im pl i f y 3 6 - x - \frac{x + 10}{3 ( 6 - x ) ^{\frac{2}{3}}}

e x p an d \frac{26}{( x + 3 ) ( x ^{2} + 4 )}

s im pl i f y (3 x - x) \cdot (3 x^{2} + x 3 x + x^{2})

e x p an d \frac{x - 4}{x - 2}