d/(dq)((c)(0.2q^2+2q+500))

Lösung

\frac{d}{d q} ((c) (0.2 q^{2} + 2 q + 500))

c (0.4 q + 2)

Schritte zur Lösung

\frac{d}{d q} ((c) (0.2 q^{2} + 2 q + 500))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d q} (0.2 q^{2} + 2 q + 500)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= c (\frac{d}{d q} (0.2 q^{2}) + \frac{d}{d q} (2 q) + \frac{d}{d q} (500))

\frac{d}{d q} (0.2 q^{2}) = 0.4 q

\frac{d}{d q} (2 q) = 2

\frac{d}{d q} (500) = 0

= c (0.4 q + 2 + 0)

Vereinfache

= c (0.4 q + 2)

e x p an d (y = 2 - x) (0.5)

e x p an d (- 4, - 5) y (6, - 1)

e x p an d \frac{- 7 x ^{8} + 9}{( x ^{8} + 9 ) ^{2}}

e x p an d a (e + 2 d)^{3} + b (e + 2 d)^{3} + c

e x p an d (e + c + f)^{2}