展开-cos(x)sec(x)tan(x)+2sec(x)sin(x)

解答

展开

- cos (x) sec (x) tan (x) + 2 sec (x) sin (x)

tan (x)

求解步骤

- cos (x) sec (x) tan (x) + 2 sec (x) sin (x)

sec (x) sin (x) = tan (x)

= 2 tan (x) - cos (x) sec (x) tan (x)

sec (x) cos (x) = 1

= tan (x) (2 - 1)

因式分解出通项

tan (x)

= tan (x) (- cos (x) sec (x) + 2)

= tan (x)

s im pl i f y a (2 - 4) b (- 3.2)

e x p an d \frac{4}{5} \times \frac{7}{9} \times \frac{1}{2}

e x p an d \frac{x ^{2} + 2 x - 35}{5 x ( x ^{2} - 1 )}

e x p an d [(\frac{1}{2})^{2} \cdot (\frac{3}{5})^{2}]^{2}

e x p an d \frac{z}{( z ^{2} - z + 1 ) ( z + 1 )}