展开 ((x+3)(x+6)^2(x+1))/((x-3)(x+4))

解答

展开

\frac{( x + 3 ) ( x + 6 ) ^{2} ( x + 1 )}{( x - 3 ) ( x + 4 )}

\frac{x ^{4} + 16 x ^{3} + 87 x ^{2} + 180 x + 108}{x ^{2} + x - 12}

求解步骤

\frac{( x + 3 ) ( x + 6 ) ^{2} ( x + 1 )}{( x - 3 ) ( x + 4 )}

(x + 6)^{2} = x^{2} + 12 x + 36

= \frac{( x + 3 ) ( x ^{2} + 12 x + 36 ) ( x + 1 )}{( x - 3 ) ( x + 4 )}

乘开

(x - 3) (x + 4) : x^{2} + x - 12

= \frac{( x + 3 ) ( x ^{2} + 12 x + 36 ) ( x + 1 )}{x ^{2} + x - 12}

乘开

(x + 3) (x^{2} + 12 x + 36) (x + 1) : x^{4} + 16 x^{3} + 87 x^{2} + 180 x + 108

= \frac{x ^{4} + 16 x ^{3} + 87 x ^{2} + 180 x + 108}{x ^{2} + x - 12}

e x p an d 0.0759 \cdot 2. 1^{5} \cdot (1 - (0, 5)^{2})

e x p an d \frac{5 x + 1}{( x + 2 ) ( x - 1 )}

e x p an d (e^{20 x} + e^{- 20 x})^{2}

e x p an d lo g_{10} (3) (x + 1) - 2

e x p an d 9 (x + 2 = 4 x - 32)