展开 (2y^2(3y^3+1))/(19)

解答

展开

\frac{2 y ^{2} ( 3 y ^{3} + 1 )}{19}

\frac{6 y ^{5}}{19} + \frac{2 y ^{2}}{19}

求解步骤

\frac{2 y ^{2} ( 3 y ^{3} + 1 )}{19}

乘开

2 y^{2} (3 y^{3} + 1) : 6 y^{5} + 2 y^{2}

= \frac{6 y ^{5} + 2 y ^{2}}{19}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 y ^{5} + 2 y ^{2}}{19} = \frac{6 y ^{5}}{19} + \frac{2 y ^{2}}{19}

= \frac{6 y ^{5}}{19} + \frac{2 y ^{2}}{19}

\frac{d ^{3}}{d x ^{3}} ((y) (2 x^{4} + 3 x^{2} + 12))

e x p an d \frac{s + 1}{s ( s - 1 ) ( s ^{2} + 4 s + 16 )}

e x p an d \frac{( 2 a - b ) - 3}{4 - 2 ( 2 a - b ) ^{2}}

e x p an d d x + (\frac{x}{y} - sin (y)) d y

e x p an d (4312 + 2) (332 - 4)