erweitern ((3x-1)^2)/9

Lösung

erweitern

\frac{( 3 x - 1 ) ^{2}}{9}

x^{2} - \frac{2 x}{3} + \frac{1}{9}

Schritte zur Lösung

\frac{( 3 x - 1 ) ^{2}}{9}

(3 x - 1)^{2} = 9 x^{2} - 6 x + 1

= \frac{9 x ^{2} - 6 x + 1}{9}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} - 6 x + 1}{9} = \frac{9 x ^{2}}{9} - \frac{6 x}{9} + \frac{1}{9}

= \frac{9 x ^{2}}{9} - \frac{6 x}{9} + \frac{1}{9}

Teile die Zahlen:

\frac{9}{9} = 1

= x^{2} - \frac{6 x}{9} + \frac{1}{9}

Streiche

\frac{6 x}{9} : \frac{2 x}{3}

= x^{2} - \frac{2 x}{3} + \frac{1}{9}

e x p an d \frac{( 3 x - 1 )}{x ( x - 4 )}

s im pl i f y 10 (lo g_{10} (2) + 7)

e x p an d \frac{5}{( 2 n + 1 ) ^{2}}

e x p an d y \frac{d ^{2}}{d ^{2} x} (y^{2} = x^{2} + 2 x)

e x p an d \frac{1}{( t ^{4} + 1 ) ^{3}}