d/(dr(T))(({E}(T,b))(10-10T*(b^{-0.14r(T)})))

Lösung

\frac{d ^{2}}{d r ( T ) d T} ((E (T, b)) (10 - 10 T \cdot (b^{- 0.14 r (T)})))

\frac{d}{d T} (E (T, b)) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b))) + 1.4 ln (b) (- 0.14 b^{- 0.14 r (T)} T ln (b) \frac{d}{d T} (r (T)) + b^{- 0.14 r (T)}) E (T, b)

Schritte zur Lösung

\frac{d ^{2}}{d r ( T ) d T} ((E (T, b)) (10 - 10 T (b^{- 0.14 r (T)})))

\frac{d}{d r ( T )} (E (T, b) (10 - 10 T b^{- 0.14 r (T)})) = E (T, b) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b)))

= \frac{d}{d T} (E (T, b) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b))))

\frac{d}{d T} (E (T, b) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b)))) = \frac{d}{d T} (E (T, b)) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b))) + 1.4 ln (b) (- 0.14 b^{- 0.14 r (T)} T ln (b) \frac{d}{d T} (r (T)) + b^{- 0.14 r (T)}) E (T, b)

= \frac{d}{d T} (E (T, b)) (0 - (- 1.4 T b^{- 0.14 r (T)} ln (b))) + 1.4 ln (b) (- 0.14 b^{- 0.14 r (T)} T ln (b) \frac{d}{d T} (r (T)) + b^{- 0.14 r (T)}) E (T, b)

e x p an d \frac{4 e ^{t} ( 1 - e ^{h} )}{h}

e x p an d \frac{( 4 - x ^{2} )}{x ( 1 + x )}

e x p an d (a_{1} e + a_{2} e^{2})^{3}

e x p an d 2 (3 - 1)

e x p an d (\frac{1}{y ^{2}}, - \frac{2 x}{y ^{3}}) \cdot (1, 0)