解答
展开 (x+2x1)14
解答
x14+7x25+491x11+291x19+161001x8+161001x13+643003x5+16429x7+2563003x2+2561001x+1024x1001+512x591+4096x491+4096x117+16384x71
求解步骤
(x+2x1)14
使用二项式定理: (a+b)n=i=0∑n(in)a(n−i)bia=x,b=2x1
=i=0∑14(i14)x(14−i)(2x1)i
展开求和
=0!(14−0)!14!x14(2x1)0+1!(14−1)!14!x13(2x1)1+2!(14−2)!14!x12(2x1)2+3!(14−3)!14!x11(2x1)3+4!(14−4)!14!x10(2x1)4+5!(14−5)!14!x9(2x1)5+6!(14−6)!14!x8(2x1)6+7!(14−7)!14!x7(2x1)7+8!(14−8)!14!x6(2x1)8+9!(14−9)!14!x5(2x1)9+10!(14−10)!14!x4(2x1)10+11!(14−11)!14!x3(2x1)11+12!(14−12)!14!x2(2x1)12+13!(14−13)!14!x1(2x1)13+14!(14−14)!14!x0(2x1)14
化简 0!(14−0)!14!x14(2x1)0:x14
化简 1!(14−1)!14!x13(2x1)1:7x225
化简 2!(14−2)!14!x12(2x1)2:491x11
化简 3!(14−3)!14!x11(2x1)3:2(x)391x11
化简 4!(14−4)!14!x10(2x1)4:161001x8
化简 5!(14−5)!14!x9(2x1)5:16(x)51001x9
化简 6!(14−6)!14!x8(2x1)6:643003x5
化简 7!(14−7)!14!x7(2x1)7:16(x)7429x7
化简 8!(14−8)!14!x6(2x1)8:2563003x2
化简 9!(14−9)!14!x5(2x1)9:256(x)91001x5
化简 10!(14−10)!14!x4(2x1)10:1024x1001
化简 11!(14−11)!14!x3(2x1)11:512(x)1191x3
化简 12!(14−12)!14!x2(2x1)12:4096x491
化简 13!(14−13)!14!x1(2x1)13:4096(x)137x
化简 14!(14−14)!14!x0(2x1)14:16384x71
=x14+7x225+491x11+2(x)391x11+161001x8+16(x)51001x9+643003x5+16(x)7429x7+2563003x2+256(x)91001x5+1024x1001+512(x)1191x3+4096x491+4096(x)137x+16384x71
化简 x14+7x225+491x11+2(x)391x11+161001x8+16(x)51001x9+643003x5+16(x)7429x7+2563003x2+256(x)91001x5+1024x1001+512(x)1191x3+4096x491+4096(x)137x+16384x71:x14+7x225+491x11+291x219+161001x8+161001x213+643003x5+16429x27+2563003x2+2561001x+1024x1001+512x2591+4096x491+4096x2117+16384x71
=x14+7x225+491x11+291x219+161001x8+161001x213+643003x5+16429x27+2563003x2+2561001x+1024x1001+512x2591+4096x491+4096x2117+16384x71
化简 x14+7x225+491x11+291x219+161001x8+161001x213+643003x5+16429x27+2563003x2+2561001x+1024x1001+512x2591+4096x491+4096x2117+16384x71:x14+7x25+491x11+291x19+161001x8+161001x13+643003x5+16429x7+2563003x2+2561001x+1024x1001+512x591+4096x491+4096x117+16384x71
=x14+7x25+491x11+291x19+161001x8+161001x13+643003x5+16429x7+2563003x2+2561001x+1024x1001+512x591+4096x491+4096x117+16384x71