展开 1+tan^2(x)

解答

展开

1 + tan^{2} (x)

sec^{2} (x)

求解步骤

1 + tan^{2} (x)

使用三角恒等式改写

= sec^{2} (x)

e x p an d (x - 1) \cdot (x - 2)^{2} \cdot (x - 3)^{3} l e f t (x - 4)^{4}

e x p an d (- 2 sin (x) - 2 sin (2 x))^{2}

e x p an d - \frac{1}{x ( 1 - ln ( x ) )}

e x p an d \frac{192 x ^{2} - 48 x + 5}{( 8 x - 5 ) ^{6}}

e x p an d \frac{- 3 s - 5 - 9 e ^{- 6 s}}{( 2 s + 8 ) ( s + 10 )}