展开 (ABC+A^'BC)(AC)

解答

展开

(A BC + A^{^{'}} BC) (A C)

A^{2} B C^{2} + B C^{2} A^{' + 1}

求解步骤

(A BC + A^{^{'}} BC) (A C)

= (A BC + BC A^{^{^{'}}}) (A C)

使用分配律:

a (b + c) = ab + a c

a = (A C), b = A BC, c = A^{^{'}} BC

= (A C) A BC + (A C) A^{^{^{'}}} BC

= A BC (A C) + BC A^{^{^{'}}} (A C)

化简

A BC (A C) + BC A^{^{'}} (A C) : A^{2} B C^{2} + B C^{2} A^{^{'} + 1}

= A^{2} B C^{2} + B C^{2} A^{^{'} + 1}

s im pl i f y (a - 7)^{2}

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