展開する-sec(x)(2sin(2x)-tan(x)cos(2x))

解

展開する

- sec (x) (2 sin (2 x) - tan (x) cos (2 x))

- 2 sec (x) sin (2 x) + cos (2 x) sec (x) tan (x)

解答ステップ

- sec (x) (2 sin (2 x) - tan (x) cos (2 x))

分配法則を適用する:

a (b - c) = ab - a c

- sec (x) (2 sin (2 x) - tan (x) cos (2 x)) = - sec (x) \cdot 2 sin (2 x) - (- sec (x)) tan (x) cos (2 x)

= - sec (x) \cdot 2 sin (2 x) - (- sec (x)) tan (x) cos (2 x)

簡素化

- sec (x) \cdot 2 sin (2 x) - (- sec (x)) tan (x) cos (2 x) : - 2 sec (x) sin (2 x) + cos (2 x) sec (x) tan (x)

= - 2 sec (x) sin (2 x) + cos (2 x) sec (x) tan (x)