erweitern (sqrt(x)+x^2)^3

Lösung

erweitern

(x + x^{2})^{3}

x x + 3 x^{3} + 3 x^{4} x + x^{6}

Schritte zur Lösung

(x + x^{2})^{3}

Wende Formel für perfekte dritte Potenzen an:

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

(x + x^{2})^{3} = (x)^{3} + 3 (x)^{2} x^{2} + 3 x (x^{2})^{2} + (x^{2})^{3}

= (x)^{3} + 3 (x)^{2} x^{2} + 3 x (x^{2})^{2} + (x^{2})^{3}

Vereinfache

(x)^{3} + 3 (x)^{2} x^{2} + 3 x (x^{2})^{2} + (x^{2})^{3} : x x + 3 x^{3} + 3 x^{4} x + x^{6}

= x x + 3 x^{3} + 3 x^{4} x + x^{6}

s im pl i f y 8 (1 + 7) + \frac{8 - 16 7}{9}

e x p an d 3 x + 2 + 3 (x + 2)^{2}

e x p an d (k^{2} - \frac{9}{2})^{2}

e x p an d \frac{a x + y + ( a x + y ) ^{2} + z ^{2}}{z}

e x p an d, (3 - 9) (3 - 5)