vereinfachen (x-1/(x^2))*(x+1/(x^2))

Lösung

vereinfachen

(x - \frac{1}{x ^{2}}) \cdot (x + \frac{1}{x ^{2}})

\frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{4}}

Schritte zur Lösung

(x - \frac{1}{x ^{2}}) (x + \frac{1}{x ^{2}})

Füge zusammen:

x - \frac{1}{x ^{2}} : \frac{x ^{3} - 1}{x ^{2}}

= \frac{x ^{3} - 1}{x ^{2}} (x + \frac{1}{x ^{2}})

Wende Bruchregel an:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{3} - 1 ) ( x + \frac{1}{x ^{2}} )}{x ^{2}}

Vereinfache

(x^{3} - 1) (x + \frac{1}{x ^{2}}) : \frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{2}}

= \frac{\frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{2}}}{x ^{2}}

Wende Bruchregel an:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{2} x ^{2}}

Vereinfache

x^{2} x^{2} : x^{4}

= \frac{( x ^{3} - 1 ) ( x ^{3} + 1 )}{x ^{4}}

e x p an d cos (2 x^{3} - 9 x) (6 x^{2} - 9)

e x p an d - 2 (2 + 3) 2 - 3

e x p an d \frac{4}{( x - 1 ) ( x + 3 )}

s im pl i f y (x + y) \cdot (x - y)

s im pl i f y (x + \frac{1}{5}) (x + \frac{2}{5})