化简 (1+e^{iθ})^2

解答

化简

(1 + e^{i θ})^{2}

(1 + cos (θ) + i sin (θ))^{2}

求解步骤

(1 + e^{i θ})^{2}

使用虚数运算法则:

e^{ia} = cos (a) + i sin (a)

= (1 + cos (θ) + i sin (θ))^{2}

e x p an d (3 x - 2) l e f t (x + 2)

e x p an d A (6, 2) y B (5, - 4)

e x p an d (- r cos (x) + v cos (y) + d)^{2}

e x p an d \frac{4}{x ( x - 1 )}

e x p an d \frac{x ( x - 5 )}{x - 25}