x^2-13x+40=0

解

x^{2} - 13 x + 40 = 0

x = 8, x = 5

解答ステップ

x^{2} - 13 x + 40 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 40 = 3

x_{1, 2} = \frac{- ( - 13 ) \pm 3}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 13 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 3}{2 \cdot 1}

x = \frac{- ( - 13 ) + 3}{2 \cdot 1} : 8

x = \frac{- ( - 13 ) - 3}{2 \cdot 1} : 5

二次equationの解:

x = 8, x = 5