y^2-4y+3=0

解

y^{2} - 4 y + 3 = 0

y = 3, y = 1

解答ステップ

y^{2} - 4 y + 3 = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

y_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

解を分離する

y_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

y = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

y = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

二次equationの解:

y = 3, y = 1