faktorisieren-2x^2+3x-1

Lösung

faktorisieren

- 2 x^{2} + 3 x - 1

- (2 x - 1) (x - 1)

Schritte zur Lösung

- 2 x^{2} + 3 x - 1

Klammere aus

- 1 : - (2 x^{2} - 3 x + 1)

= - (2 x^{2} - 3 x + 1)

Faktorisiere

2 x^{2} - 3 x + 1 : (2 x - 1) (x - 1)

= - (2 x - 1) (x - 1)

\frac{k}{7} \geq - \frac{1}{7}

\frac{16}{9} = 8 y

f a c t or 16 g^{3} + 2 h^{3}

\frac{126}{150} = \frac{x}{75}

x^{2} + (x + 1)^{2} = 25