簡約 2/3 xy^2+2x-1/3 xy^2+2/3 x^2y-5x

解

簡約

\frac{2}{3} x y^{2} + 2 x - \frac{1}{3} x y^{2} + \frac{2}{3} x^{2} y - 5 x

- 3 x + \frac{1}{3} x y^{2} + \frac{2}{3} x^{2} y

解答ステップ

\frac{2}{3} x y^{2} + 2 x - \frac{1}{3} x y^{2} + \frac{2}{3} x^{2} y - 5 x

条件のようなグループ

= 2 x - 5 x + \frac{2}{3} x y^{2} - \frac{1}{3} x y^{2} + \frac{2}{3} x^{2} y

類似した元を足す:

2 x - 5 x = - 3 x

= - 3 x + \frac{2}{3} x y^{2} - \frac{1}{3} x y^{2} + \frac{2}{3} x^{2} y

共通項をくくり出す

x y^{2} : x y^{2} (\frac{2}{3} - \frac{1}{3})

= - 3 x + x y^{2} (\frac{2}{3} - \frac{1}{3}) + \frac{2}{3} x^{2} y

\frac{2}{3} - \frac{1}{3} = \frac{1}{3}

= - 3 x + x y^{2} \frac{1}{3} + \frac{2}{3} x^{2} y

= - 3 x + \frac{1}{3} x y^{2} + \frac{2}{3} x^{2} y