x^3+3x^2-x-3>= 0

Lösung

x^{3} + 3 x^{2} - x - 3 \geq 0

- 3 \leq x \leq - 1 or x \geq 1

Intervall-Notation

[- 3, - 1] \cup [1, \infty)

Schritte zur Lösung

x^{3} + 3 x^{2} - x - 3 \geq 0

Faktorisiere

x^{3} + 3 x^{2} - x - 3 : (x + 3) (x + 1) (x - 1)

(x + 3) (x + 1) (x - 1) \geq 0

Identifiziere die Intervalle

- 3 \leq x \leq - 1 or x \geq 1

f a c t or - 3 + 6

∣ 4 x + 8 ∣ - 5 = - 5

x^{2} - 10 x - 9 = 2 x

2 x^{2} + 13 x + 21 = 0

(4 x + 4)^{2} - 4 = 0