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Frequently Asked Questions (FAQ)
What are the solutions to the equation 2y^2-y-5=0 ?
- The solutions to the equation 2y^2-y-5=0 are y=(1+sqrt(41))/4 ,y=(1-sqrt(41))/4
Find the zeros of 2y^2-y-5=0
- The zeros of 2y^2-y-5=0 are y=(1+sqrt(41))/4 ,y=(1-sqrt(41))/4