faktorisieren x^2-10x+25-y^2

Lösung

faktorisieren

x^{2} - 10 x + 25 - y^{2}

(x - 5 + y) (x - 5 - y)

Schritte zur Lösung

x^{2} - 10 x + 25 - y^{2}

Faktorisiere

x^{2} - 10 x + 25 : (x - 5)^{2}

= (x - 5)^{2} - y^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(x - 5)^{2} - y^{2} = ((x - 5) + y) ((x - 5) - y)

= ((x - 5) + y) ((x - 5) - y)

Apply rule:

(a) = a

(x - 5) = x - 5

= (x - 5 + y) (x - 5 - y)

\frac{1}{3} (x + 4) - \frac{5}{6} (x - 3) > \frac{1}{2} x + 1

x^{2} - 12 \leq 4 x

s im pl i f y \frac{m ^{2} - 7 m - 18}{m ^{2} - 10 m + 9} + \frac{6}{m - 1}

s im pl i f y \frac{( x + 6 ) ^{2}}{25} + \frac{( y - 5 ) ^{2}}{36}

s im pl i f y \frac{2 9 ^{3} \cdot e ^{- 29}}{3 !}