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Frequently Asked Questions (FAQ)
What are the solutions to the equation 5y^2-7y+1=0 ?
- The solutions to the equation 5y^2-7y+1=0 are y=(7+sqrt(29))/(10),y=(7-sqrt(29))/(10)
Find the zeros of 5y^2-7y+1=0
- The zeros of 5y^2-7y+1=0 are y=(7+sqrt(29))/(10),y=(7-sqrt(29))/(10)