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شائع Word Problems >

the sum of 3 consecutive even numbers is 1208. what are the numbers

الحلّ

t h e s u m o f 3 co n sec u t i v e e v e n n u mb ers i s 1208. w ha t a re t h e n u mb ers

الحلّ

The numbers : 400 \frac{2}{3}, 402 \frac{2}{3}, 404 \frac{2}{3}

خطوات الحلّ

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x + x + 2 + x + 4 = 1208

x + x + 2 + x + 4 = 1208

حلّ:

x = \frac{1202}{3}

x + 2 = \frac{1202}{3} + 2 = \frac{1208}{3}

x + 4 = \frac{1202}{3} + 4 = \frac{1214}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{1202}{3} = 400 \frac{2}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{1208}{3} = 402 \frac{2}{3}

حوّل من كسر تخيّليّ لعدد مختلط:

\frac{1214}{3} = 404 \frac{2}{3}

The numbers : 400 \frac{2}{3}, 402 \frac{2}{3}, 404 \frac{2}{3}

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