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受欢迎的三角函数 >

sec(θ)+sqrt(2)=0

解答

sec (θ) + 2 = 0

解答

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

+1

度数

θ = 13 5^{\circ} + 36 0^{\circ} n, θ = 22 5^{\circ} + 36 0^{\circ} n

求解步骤

sec (θ) + 2 = 0

将

2

到右边

sec (θ) + 2 = 0

两边减去

2

sec (θ) + 2 - 2 = 0 - 2

化简

sec (θ) = - 2

sec (θ) = - 2

sec (θ) = - 2

的通解

sec (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

作图

流行的例子

sec((3θ)/2)=-2

sec (\frac{3 θ}{2}) = - 2

cos(2x)+sin(x)=0

cos (2 x) + sin (x) = 0

arctan((sqrt(3))/3)

arctan (\frac{3}{3})

cos^2(x)-3sin^2(x)=0

cos^{2} (x) - 3 sin^{2} (x) = 0

tan(arccos(-(sqrt(3))/2))

tan (arccos (- \frac{3}{2}))