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受欢迎的三角函数 >

2x=sin(90)

解答

2 x = sin (9 0^{\circ})

解答

x = \frac{1}{2}

+1

十进制

x = 0.5

求解步骤

2 x = sin (9 0^{\circ})

化简

sin (9 0^{\circ}) : 1

sin (9 0^{\circ})

使用以下普通恒等式:

sin (9 0^{\circ}) = 1

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

2 x = 1

两边除以

2

2 x = 1

两边除以

2

\frac{2 x}{2} = \frac{1}{2}

化简

x = \frac{1}{2}

x = \frac{1}{2}

作图

流行的例子

solvefor c,10cos(x)-24sin(2x)=13

so l v e f or c, 10 cos (x) - 24 sin (2 x) = 13

solvefor y,d^2-4d+4y=e^2x+x^2+x+sin^2(x)

so l v e f or y, d^{2} - 4 d + 4 y = e^{2} x + x^{2} + x + sin^{2} (x)

solvefor y,(d^2-5d+6)*y=x+sin^3(x)

so l v e f or y, (d^{2} - 5 d + 6) \cdot y = x + sin^{3} (x)

solvefor t,cot(x)sin^2(x)=1+cos^2(x)

so l v e f or t, cot (x) sin^{2} (x) = 1 + cos^{2} (x)

solvefor f,(6)f=t^{sin(t)}

so l v e f or f, (6) f = t^{s i n (t)}