cot(β)=(-sqrt(3))/3

Lösung

cot (β) = \frac{- 3}{3}

β = \frac{2 π}{3} + πn

Grad

β = 12 0^{\circ} + 18 0^{\circ} n

Schritte zur Lösung

cot (β) = \frac{- 3}{3}

Wende Bruchregel an:

\frac{- a}{b} = - \frac{a}{b}

cot (β) = - \frac{3}{3}

Allgemeine Lösung für

cot (β) = - \frac{3}{3}

cot (x)

Periodizitätstabelle mit

πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

β = \frac{2 π}{3} + πn

β = \frac{2 π}{3} + πn

2 sin^{2} (3 x) - 3 cos (3 x) + 1 = 0

sin (θ) = \frac{15}{23}

3 sin^{2} (x) + 6 sin (x) - 11 = 7 sin (x) - 9

sin^{2} (a) = 2 sin (a)

sin (3 x - 50) cos (x) - cos (3 x - 50) sin (x) = 0, 0^{\circ} \leq x \leq 18 0^{\circ}