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شائع علم المثلثات >

solvefor y,(sin(3y))/3 =(cos(2x))/2+1/2

الحلّ

solve for

y, \frac{sin ( 3 y )}{3} = \frac{cos ( 2 x )}{2} + \frac{1}{2}

الحلّ

y = \frac{arcsin ( \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}, y = \frac{π}{3} + \frac{arcsin ( - \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

خطوات الحلّ

\frac{sin ( 3 y )}{3} = \frac{cos ( 2 x )}{2} + \frac{1}{2}

3

اضرب الطرفين بـ

\frac{sin ( 3 y )}{3} = \frac{cos ( 2 x )}{2} + \frac{1}{2}

3

اضرب الطرفين بـ

\frac{3 sin ( 3 y )}{3} = 3 \cdot \frac{cos ( 2 x )}{2} + 3 \cdot \frac{1}{2}

بسّط

\frac{3 sin ( 3 y )}{3} = 3 \cdot \frac{cos ( 2 x )}{2} + 3 \cdot \frac{1}{2}

\frac{3 sin ( 3 y )}{3}

بسّط:

sin (3 y)

\frac{3 sin ( 3 y )}{3}

\frac{3}{3} = 1 :

اقسم الأعداد

= sin (3 y)

3 \cdot \frac{cos ( 2 x )}{2} + 3 \cdot \frac{1}{2}

بسّط:

\frac{3 cos ( 2 x ) + 3}{2}

3 \cdot \frac{cos ( 2 x )}{2} + 3 \cdot \frac{1}{2}

3 \cdot \frac{cos ( 2 x )}{2} = \frac{3 cos ( 2 x )}{2}

3 \cdot \frac{cos ( 2 x )}{2}

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= \frac{cos ( 2 x ) \cdot 3}{2}

3 \cdot \frac{1}{2} = \frac{3}{2}

3 \cdot \frac{1}{2}

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= \frac{1 \cdot 3}{2}

1 \cdot 3 = 3 :

اضرب الأعداد

= \frac{3}{2}

= \frac{3 cos ( 2 x )}{2} + \frac{3}{2}

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

فعّل القانون

= \frac{3 cos ( 2 x ) + 3}{2}

sin (3 y) = \frac{3 cos ( 2 x ) + 3}{2}

sin (3 y) = \frac{3 cos ( 2 x ) + 3}{2}

sin (3 y) = \frac{3 cos ( 2 x ) + 3}{2}

Apply trig inverse properties

sin (3 y) = \frac{3 cos ( 2 x ) + 3}{2}

sin (3 y) = \frac{3 cos ( 2 x ) + 3}{2} :

حلول عامّة لـ

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

3 y = arcsin (\frac{3 cos ( 2 x ) + 3}{2}) + 2 πn, 3 y = π + arcsin (- \frac{3 cos ( 2 x ) + 3}{2}) + 2 πn

3 y = arcsin (\frac{3 cos ( 2 x ) + 3}{2}) + 2 πn, 3 y = π + arcsin (- \frac{3 cos ( 2 x ) + 3}{2}) + 2 πn

3 y = arcsin (\frac{3 cos ( 2 x ) + 3}{2}) + 2 πn

حلّ:

y = \frac{arcsin ( \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

3 y = arcsin (\frac{3 cos ( 2 x ) + 3}{2}) + 2 πn

3

اقسم الطرفين على

3 y = arcsin (\frac{3 cos ( 2 x ) + 3}{2}) + 2 πn

3

اقسم الطرفين على

\frac{3 y}{3} = \frac{arcsin ( \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

بسّط

y = \frac{arcsin ( \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

y = \frac{arcsin ( \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

3 y = π + arcsin (- \frac{3 cos ( 2 x ) + 3}{2}) + 2 πn

حلّ:

y = \frac{π}{3} + \frac{arcsin ( - \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

3 y = π + arcsin (- \frac{3 cos ( 2 x ) + 3}{2}) + 2 πn

3

اقسم الطرفين على

3 y = π + arcsin (- \frac{3 cos ( 2 x ) + 3}{2}) + 2 πn

3

اقسم الطرفين على

\frac{3 y}{3} = \frac{π}{3} + \frac{arcsin ( - \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

بسّط

y = \frac{π}{3} + \frac{arcsin ( - \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

y = \frac{π}{3} + \frac{arcsin ( - \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

y = \frac{arcsin ( \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}, y = \frac{π}{3} + \frac{arcsin ( - \frac{3 c o s ( 2 x ) + 3}{2} )}{3} + \frac{2 πn}{3}

رسم

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