cos(θ)=(2sqrt(3))/5

Lösung

cos (θ) = \frac{2 3}{5}

θ = 0.80540 \dots + 2 πn, θ = 2 π - 0.80540 \dots + 2 πn

Grad

θ = 46.14622 \dots^{\circ} + 36 0^{\circ} n, θ = 313.85377 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{2 3}{5}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{2 3}{5}

Allgemeine Lösung für

cos (θ) = \frac{2 3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2 3}{5}) + 2 πn, θ = 2 π - arccos (\frac{2 3}{5}) + 2 πn

θ = arccos (\frac{2 3}{5}) + 2 πn, θ = 2 π - arccos (\frac{2 3}{5}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.80540 \dots + 2 πn, θ = 2 π - 0.80540 \dots + 2 πn

cos (2 x) (sin (x) + \frac{2}{2}) = 0

5 sin (θ) = 5

2 sin (3 x) = 2, 0 \leq x \leq 2 π

1 - tan (x) = 0

2 cos^{2} (x) - 3 cos (x) = 0, 0^{\circ} < x < 18 0^{\circ}