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人気のある三角関数 >

3/(cos^2(x))=(7+4)/(cot(x))

解

\frac{3}{cos ^{2} ( x )} = \frac{7 + 4}{cot ( x )}

解

x = \frac{0.57693 \dots}{2} + πn, x = \frac{π}{2} - \frac{0.57693 \dots}{2} + πn

+1

度

x = 16.52786 \dots^{\circ} + 18 0^{\circ} n, x = 73.47213 \dots^{\circ} + 18 0^{\circ} n

解答ステップ

\frac{3}{cos ^{2} ( x )} = \frac{7 + 4}{cot ( x )}

両辺から

\frac{7 + 4}{cot ( x )}

を引く

\frac{3}{cos ^{2} ( x )} - \frac{11}{cot ( x )} = 0

簡素化

\frac{3}{cos ^{2} ( x )} - \frac{11}{cot ( x )} : \frac{3 cot ( x ) - 11 cos ^{2} ( x )}{cos ^{2} ( x ) cot ( x )}

\frac{3}{cos ^{2} ( x )} - \frac{11}{cot ( x )}

以下の最小公倍数:

cos^{2} (x), cot (x) : cos^{2} (x) cot (x)

cos^{2} (x), cot (x)

最小公倍数 (LCM)

cos^{2} (x)

または以下のいずれかに現れる因数で構成された式を計算する:

cot (x)

= cos^{2} (x) cot (x)

LCMに基づいて分数を調整する

該当する分母を乗じてLCMに変えるために

必要な量で各分子を乗じる

cos^{2} (x) cot (x)

\frac{3}{cos ^{2} ( x )}

の場合

:

分母と分子に以下を乗じる:

cot (x)

\frac{3}{cos ^{2} ( x )} = \frac{3 cot ( x )}{cos ^{2} ( x ) cot ( x )}

\frac{11}{cot ( x )}

の場合

:

分母と分子に以下を乗じる:

cos^{2} (x)

\frac{11}{cot ( x )} = \frac{11 cos ^{2} ( x )}{cot ( x ) cos ^{2} ( x )}

= \frac{3 cot ( x )}{cos ^{2} ( x ) cot ( x )} - \frac{11 cos ^{2} ( x )}{cot ( x ) cos ^{2} ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 cot ( x ) - 11 cos ^{2} ( x )}{cos ^{2} ( x ) cot ( x )}

\frac{3 cot ( x ) - 11 cos ^{2} ( x )}{cos ^{2} ( x ) cot ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 cot (x) - 11 cos^{2} (x) = 0

サイン, コサインで表わす

- 11 cos^{2} (x) + 3 cot (x)

基本的な三角関数の公式を使用する:

cot (x) = \frac{cos ( x )}{sin ( x )}

= - 11 cos^{2} (x) + 3 \cdot \frac{cos ( x )}{sin ( x )}

簡素化

- 11 cos^{2} (x) + 3 \cdot \frac{cos ( x )}{sin ( x )} : \frac{- 11 cos ^{2} ( x ) sin ( x ) + 3 cos ( x )}{sin ( x )}

- 11 cos^{2} (x) + 3 \cdot \frac{cos ( x )}{sin ( x )}

乗じる

3 \cdot \frac{cos ( x )}{sin ( x )} : \frac{3 cos ( x )}{sin ( x )}

3 \cdot \frac{cos ( x )}{sin ( x )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{cos ( x ) \cdot 3}{sin ( x )}

= - 11 cos^{2} (x) + \frac{3 cos ( x )}{sin ( x )}

元を分数に変換する:

11 cos^{2} (x) = \frac{11 cos ^{2} ( x ) sin ( x )}{sin ( x )}

= - \frac{11 cos ^{2} ( x ) sin ( x )}{sin ( x )} + \frac{cos ( x ) \cdot 3}{sin ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 11 cos ^{2} ( x ) sin ( x ) + cos ( x ) \cdot 3}{sin ( x )}

= \frac{- 11 cos ^{2} ( x ) sin ( x ) + 3 cos ( x )}{sin ( x )}

\frac{3 cos ( x ) - 11 cos ^{2} ( x ) sin ( x )}{sin ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 cos (x) - 11 cos^{2} (x) sin (x) = 0

因数

3 cos (x) - 11 cos^{2} (x) sin (x) : cos (x) (3 - 11 sin (x) cos (x))

3 cos (x) - 11 cos^{2} (x) sin (x)

指数の規則を適用する:

a^{b + c} = a^{b} a^{c}

sin (x) cos^{2} (x) = cos (x) cos (x)

= 3 cos (x) - 11 cos (x) cos (x)

共通項をくくり出す

cos (x)

= cos (x) (3 - 11 sin (x) cos (x))

cos (x) (3 - 11 sin (x) cos (x)) = 0

各部分を別個に解く

cos (x) = 0 or 3 - 11 sin (x) cos (x) = 0

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 0

以下の一般解

cos (x) = 0

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

3 - 11 sin (x) cos (x) = 0 : x = \frac{arcsin ( \frac{6}{11} )}{2} + πn, x = \frac{π}{2} - \frac{arcsin ( \frac{6}{11} )}{2} + πn

3 - 11 sin (x) cos (x) = 0

三角関数の公式を使用して書き換える

3 - 11 sin (x) cos (x)

2倍角の公式を使用:

2 sin (x) cos (x) = sin (2 x)

sin (x) cos (x) = \frac{sin ( 2 x )}{2}

= 3 - 11 \cdot \frac{sin ( 2 x )}{2}

3 - 11 \cdot \frac{sin ( 2 x )}{2} = 0

3

を右側に移動します

3 - 11 \cdot \frac{sin ( 2 x )}{2} = 0

両辺から

3

を引く

3 - 11 \cdot \frac{sin ( 2 x )}{2} - 3 = 0 - 3

簡素化

- 11 \cdot \frac{sin ( 2 x )}{2} = - 3

- 11 \cdot \frac{sin ( 2 x )}{2} = - 3

改良

- 11 \cdot \frac{sin ( 2 x )}{2} : - \frac{11 sin ( 2 x )}{2}

- 11 \cdot \frac{sin ( 2 x )}{2}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{sin ( 2 x ) \cdot 11}{2}

- \frac{11 sin ( 2 x )}{2} = - 3

以下で両辺を乗じる:

2

- \frac{11 sin ( 2 x )}{2} = - 3

以下で両辺を乗じる:

2

- \frac{11 sin ( 2 x )}{2} \cdot 2 = - 3 \cdot 2

簡素化

- \frac{11 sin ( 2 x )}{2} \cdot 2 = - 3 \cdot 2

簡素化

- \frac{11 sin ( 2 x )}{2} \cdot 2 : - 11 sin (2 x)

- \frac{11 sin ( 2 x )}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{11 sin ( 2 x ) \cdot 2}{2}

共通因数を約分する:

2

= - 11 sin (2 x)

簡素化

- 3 \cdot 2 : - 6

- 3 \cdot 2

数を乗じる:

3 \cdot 2 = 6

= - 6

- 11 sin (2 x) = - 6

- 11 sin (2 x) = - 6

- 11 sin (2 x) = - 6

以下で両辺を割る

- 11

- 11 sin (2 x) = - 6

以下で両辺を割る

- 11

\frac{- 11 sin ( 2 x )}{- 11} = \frac{- 6}{- 11}

簡素化

sin (2 x) = \frac{6}{11}

sin (2 x) = \frac{6}{11}

三角関数の逆数プロパティを適用する

sin (2 x) = \frac{6}{11}

以下の一般解

sin (2 x) = \frac{6}{11}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

2 x = arcsin (\frac{6}{11}) + 2 πn, 2 x = π - arcsin (\frac{6}{11}) + 2 πn

2 x = arcsin (\frac{6}{11}) + 2 πn, 2 x = π - arcsin (\frac{6}{11}) + 2 πn

解く

2 x = arcsin (\frac{6}{11}) + 2 πn : x = \frac{arcsin ( \frac{6}{11} )}{2} + πn

2 x = arcsin (\frac{6}{11}) + 2 πn

以下で両辺を割る

2

2 x = arcsin (\frac{6}{11}) + 2 πn

以下で両辺を割る

2

\frac{2 x}{2} = \frac{arcsin ( \frac{6}{11} )}{2} + \frac{2 πn}{2}

簡素化

x = \frac{arcsin ( \frac{6}{11} )}{2} + πn

x = \frac{arcsin ( \frac{6}{11} )}{2} + πn

解く

2 x = π - arcsin (\frac{6}{11}) + 2 πn : x = \frac{π}{2} - \frac{arcsin ( \frac{6}{11} )}{2} + πn

2 x = π - arcsin (\frac{6}{11}) + 2 πn

以下で両辺を割る

2

2 x = π - arcsin (\frac{6}{11}) + 2 πn

以下で両辺を割る

2

\frac{2 x}{2} = \frac{π}{2} - \frac{arcsin ( \frac{6}{11} )}{2} + \frac{2 πn}{2}

簡素化

x = \frac{π}{2} - \frac{arcsin ( \frac{6}{11} )}{2} + πn

x = \frac{π}{2} - \frac{arcsin ( \frac{6}{11} )}{2} + πn

x = \frac{arcsin ( \frac{6}{11} )}{2} + πn, x = \frac{π}{2} - \frac{arcsin ( \frac{6}{11} )}{2} + πn

すべての解を組み合わせる

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = \frac{arcsin ( \frac{6}{11} )}{2} + πn, x = \frac{π}{2} - \frac{arcsin ( \frac{6}{11} )}{2} + πn

equationは以下で未定義のため:

\frac{π}{2} + 2 πn, \frac{3 π}{2} + 2 πn

x = \frac{arcsin ( \frac{6}{11} )}{2} + πn, x = \frac{π}{2} - \frac{arcsin ( \frac{6}{11} )}{2} + πn

10進法形式で解を証明する

x = \frac{0.57693 \dots}{2} + πn, x = \frac{π}{2} - \frac{0.57693 \dots}{2} + πn

グラフ

人気の例

sin (x) = 0.01

sin(x)-sin(2x)=sin^3(x)

sin (x) - sin (2 x) = sin^{3} (x)

-sin^2(x)=cos(2x)

- sin^{2} (x) = cos (2 x)

sin(x)= 4/5 , pi/2 <= 0<pi,sin(2x)

sin (x) = \frac{4}{5}, \frac{π}{2} \leq 0 < π, sin (2 x)

2cos^2(θ)-3cos(θ)+1=0,(3pi)/2 <θ<2pi

2 cos^{2} (θ) - 3 cos (θ) + 1 = 0, \frac{3 π}{2} < θ < 2 π