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인기 있는 삼각법 >

3tan^3(x)-1=0

해법

3 tan^{3} (x) - 1 = 0

해법

x = 0.60625 \dots + πn

+1

도

x = 34.73594 \dots^{\circ} + 18 0^{\circ} n

솔루션 단계

3 tan^{3} (x) - 1 = 0

대체로 해결

3 tan^{3} (x) - 1 = 0

하게:

tan (x) = u

3 u^{3} - 1 = 0

3 u^{3} - 1 = 0 : u = 3 \frac{1}{3}, u = - \frac{3 ^{\frac{2}{3}}}{6} + i \frac{6 3}{2}, u = - \frac{3 ^{\frac{2}{3}}}{6} - i \frac{6 3}{2}

3 u^{3} - 1 = 0

1

를 오른쪽으로 이동

3 u^{3} - 1 = 0

더하다

1

양쪽으로

3 u^{3} - 1 + 1 = 0 + 1

단순화

3 u^{3} = 1

3 u^{3} = 1

양쪽을 다음으로 나눕니다

3

3 u^{3} = 1

양쪽을 다음으로 나눕니다

3

\frac{3 u ^{3}}{3} = \frac{1}{3}

단순화

u^{3} = \frac{1}{3}

u^{3} = \frac{1}{3}

용

x^{3} = f (a)

해결책은

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

u = 3 \frac{1}{3}, u = 3 \frac{1}{3} \frac{- 1 + 3 i}{2}, u = 3 \frac{1}{3} \frac{- 1 - 3 i}{2}

3 \frac{1}{3} \frac{- 1 + 3 i}{2}

단순화하세요:

- \frac{3 ^{\frac{2}{3}}}{6} + i \frac{6 3}{2}

3 \frac{1}{3} \frac{- 1 + 3 i}{2}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 1 + 3 i ) 3 \frac{1}{3}}{2}

3 \frac{1}{3} = \frac{1}{3 3}

3 \frac{1}{3}

급진적인 규칙 적용:

n \frac{a}{b} = \frac{n a}{n b},

라면

a \geq 0, b \geq 0

= \frac{3 1}{3 3}

규칙 적용

n 1 = 1

31 = 1

= \frac{1}{3 3}

= \frac{\frac{1}{3 3} ( - 1 + 3 i )}{2}

(- 1 + 3 i) \frac{1}{3 3}

곱하다

: \frac{- 1 + 3 i}{3 3}

(- 1 + 3 i) \frac{1}{3 3}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( - 1 + 3 i )}{3 3}

1 \cdot (- 1 + 3 i) = - 1 + 3 i

1 \cdot (- 1 + 3 i)

곱하다:

1 \cdot (- 1 + 3 i) = (- 1 + 3 i)

= (- 1 + 3 i)

괄호 제거:

(- a) = - a

= - 1 + 3 i

= \frac{- 1 + 3 i}{3 3}

= \frac{\frac{- 1 + 3 i}{3 3}}{2}

분수 규칙 적용:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{- 1 + 3 i}{3 3 \cdot 2}

\frac{- 1 + 3 i}{2 3 3}

합리화합니다 :

\frac{3 ^{\frac{2}{3}} ( - 1 + 3 i )}{6}

\frac{- 1 + 3 i}{2 3 3}

공역에 곱셈

\frac{3 ^{\frac{2}{3}}}{3 ^{\frac{2}{3}}}

= \frac{( - 1 + 3 i ) \cdot 3 ^{\frac{2}{3}}}{3 3 \cdot 2 \cdot 3 ^{\frac{2}{3}}}

33 \cdot 2 \cdot 3^{\frac{2}{3}} = 6

33 \cdot 2 \cdot 3^{\frac{2}{3}}

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

3^{\frac{2}{3}} 33 = 3^{\frac{2}{3}} \cdot 3^{\frac{1}{3}} = 3^{\frac{2}{3} + \frac{1}{3}}

= 3^{\frac{2}{3} + \frac{1}{3}} \cdot 2

3^{\frac{2}{3} + \frac{1}{3}} = 3

3^{\frac{2}{3} + \frac{1}{3}}

분수를 합치다

\frac{2}{3} + \frac{1}{3} : 1

규칙 적용

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

숫자 추가:

2 + 1 = 3

= \frac{3}{3}

규칙 적용

\frac{a}{a} = 1

= 1

= 3^{1}

규칙 적용

a^{1} = a

= 3

= 3 \cdot 2

숫자를 곱하시오:

3 \cdot 2 = 6

= 6

= \frac{3 ^{\frac{2}{3}} ( - 1 + 3 i )}{6}

= \frac{3 ^{\frac{2}{3}} ( - 1 + 3 i )}{6}

다시 쓰다

\frac{3 ^{\frac{2}{3}} ( - 1 + 3 i )}{6}

표준복합형태로:

- \frac{3 ^{\frac{2}{3}}}{6} + \frac{6 3}{2} i

\frac{3 ^{\frac{2}{3}} ( - 1 + 3 i )}{6}

6

요인:

2 \cdot 3

6 = 2 \cdot 3

인수

= \frac{3 ^{\frac{2}{3}} ( - 1 + 3 i )}{2 \cdot 3}

\frac{3 ^{\frac{2}{3}} ( - 1 + 3 i )}{2 \cdot 3}

취소하다 :

\frac{- 1 + 3 i}{2 \cdot 3 ^{\frac{1}{3}}}

\frac{3 ^{\frac{2}{3}} ( - 1 + 3 i )}{2 \cdot 3}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{2}{3}}}{3} = \frac{1}{3 ^{1 - \frac{2}{3}}}

= \frac{- 1 + 3 i}{2 \cdot 3 ^{- \frac{2}{3} + 1}}

숫자를 빼세요:

1 - \frac{2}{3} = \frac{1}{3}

= \frac{- 1 + 3 i}{2 \cdot 3 ^{\frac{1}{3}}}

= \frac{- 1 + 3 i}{2 \cdot 3 ^{\frac{1}{3}}}

3^{\frac{1}{3}} = 33

급진적인 규칙 적용:

a^{\frac{1}{n}} = n a

3^{\frac{1}{3}} = 33

= \frac{- 1 + 3 i}{2 3 3}

분수 규칙 적용:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 1 + 3 i}{2 3 3} = - \frac{1}{2 3 3} + \frac{3 i}{2 3 3}

= - \frac{1}{2 3 3} + \frac{3 i}{2 3 3}

\frac{3 i}{2 3 3}

취소하다 :

\frac{6 3 i}{2}

\frac{3 i}{2 3 3}

\frac{3 i}{2 3 3}

취소하다 :

\frac{6 3 i}{2}

\frac{3 i}{2 3 3}

급진적인 규칙 적용:

n a = a^{\frac{1}{n}}

33 = 3^{\frac{1}{3}}, 3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}} i}{2 \cdot 3 ^{\frac{1}{3}}}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{3 ^{\frac{1}{2}}}{3 ^{\frac{1}{3}}} = 3^{\frac{1}{2} - \frac{1}{3}}

= \frac{3 ^{\frac{1}{2} - \frac{1}{3}} i}{2}

숫자를 빼세요:

\frac{1}{2} - \frac{1}{3} = \frac{1}{6}

= \frac{3 ^{\frac{1}{6}} i}{2}

급진적인 규칙 적용:

a^{\frac{1}{n}} = n a

3^{\frac{1}{6}} = 63

= \frac{6 3 i}{2}

= \frac{6 3 i}{2}

= - \frac{1}{2 3 3} + \frac{6 3 i}{2}

- \frac{1}{2 3 3} = - \frac{3 ^{\frac{2}{3}}}{6}

- \frac{1}{2 3 3}

공역에 곱셈

\frac{3 ^{\frac{2}{3}}}{3 ^{\frac{2}{3}}}

= - \frac{1 \cdot 3 ^{\frac{2}{3}}}{2 3 3 \cdot 3 ^{\frac{2}{3}}}

1 \cdot 3^{\frac{2}{3}} = 3^{\frac{2}{3}}

233 \cdot 3^{\frac{2}{3}} = 6

233 \cdot 3^{\frac{2}{3}}

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

3^{\frac{2}{3}} 33 = 3^{\frac{2}{3}} \cdot 3^{\frac{1}{3}} = 3^{\frac{2}{3} + \frac{1}{3}}

= 2 \cdot 3^{\frac{2}{3} + \frac{1}{3}}

3^{\frac{2}{3} + \frac{1}{3}} = 3

3^{\frac{2}{3} + \frac{1}{3}}

분수를 합치다

\frac{2}{3} + \frac{1}{3} : 1

규칙 적용

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

숫자 추가:

2 + 1 = 3

= \frac{3}{3}

규칙 적용

\frac{a}{a} = 1

= 1

= 3^{1}

규칙 적용

a^{1} = a

= 3

= 2 \cdot 3

숫자를 곱하시오:

2 \cdot 3 = 6

= 6

= - \frac{3 ^{\frac{2}{3}}}{6}

= - \frac{3 ^{\frac{2}{3}}}{6} + \frac{6 3}{2} i

= - \frac{3 ^{\frac{2}{3}}}{6} + \frac{6 3}{2} i

3 \frac{1}{3} \frac{- 1 - 3 i}{2}

단순화하세요:

- \frac{3 ^{\frac{2}{3}}}{6} - i \frac{6 3}{2}

3 \frac{1}{3} \frac{- 1 - 3 i}{2}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 1 - 3 i ) 3 \frac{1}{3}}{2}

3 \frac{1}{3} = \frac{1}{3 3}

3 \frac{1}{3}

급진적인 규칙 적용:

n \frac{a}{b} = \frac{n a}{n b},

라면

a \geq 0, b \geq 0

= \frac{3 1}{3 3}

규칙 적용

n 1 = 1

31 = 1

= \frac{1}{3 3}

= \frac{\frac{1}{3 3} ( - 1 - 3 i )}{2}

(- 1 - 3 i) \frac{1}{3 3}

곱하다

: \frac{- 1 - 3 i}{3 3}

(- 1 - 3 i) \frac{1}{3 3}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( - 1 - 3 i )}{3 3}

1 \cdot (- 1 - 3 i) = - 1 - 3 i

1 \cdot (- 1 - 3 i)

곱하다:

1 \cdot (- 1 - 3 i) = (- 1 - 3 i)

= (- 1 - 3 i)

괄호 제거:

(- a) = - a

= - 1 - 3 i

= \frac{- 1 - 3 i}{3 3}

= \frac{\frac{- 1 - 3 i}{3 3}}{2}

분수 규칙 적용:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{- 1 - 3 i}{3 3 \cdot 2}

\frac{- 1 - 3 i}{2 3 3}

합리화합니다 :

\frac{3 ^{\frac{2}{3}} ( - 1 - 3 i )}{6}

\frac{- 1 - 3 i}{2 3 3}

공역에 곱셈

\frac{3 ^{\frac{2}{3}}}{3 ^{\frac{2}{3}}}

= \frac{( - 1 - 3 i ) \cdot 3 ^{\frac{2}{3}}}{3 3 \cdot 2 \cdot 3 ^{\frac{2}{3}}}

33 \cdot 2 \cdot 3^{\frac{2}{3}} = 6

33 \cdot 2 \cdot 3^{\frac{2}{3}}

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

3^{\frac{2}{3}} 33 = 3^{\frac{2}{3}} \cdot 3^{\frac{1}{3}} = 3^{\frac{2}{3} + \frac{1}{3}}

= 3^{\frac{2}{3} + \frac{1}{3}} \cdot 2

3^{\frac{2}{3} + \frac{1}{3}} = 3

3^{\frac{2}{3} + \frac{1}{3}}

분수를 합치다

\frac{2}{3} + \frac{1}{3} : 1

규칙 적용

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

숫자 추가:

2 + 1 = 3

= \frac{3}{3}

규칙 적용

\frac{a}{a} = 1

= 1

= 3^{1}

규칙 적용

a^{1} = a

= 3

= 3 \cdot 2

숫자를 곱하시오:

3 \cdot 2 = 6

= 6

= \frac{3 ^{\frac{2}{3}} ( - 1 - 3 i )}{6}

= \frac{3 ^{\frac{2}{3}} ( - 1 - 3 i )}{6}

다시 쓰다

\frac{3 ^{\frac{2}{3}} ( - 1 - 3 i )}{6}

표준복합형태로:

- \frac{3 ^{\frac{2}{3}}}{6} - \frac{6 3}{2} i

\frac{3 ^{\frac{2}{3}} ( - 1 - 3 i )}{6}

6

요인:

2 \cdot 3

6 = 2 \cdot 3

인수

= \frac{3 ^{\frac{2}{3}} ( - 1 - 3 i )}{2 \cdot 3}

\frac{3 ^{\frac{2}{3}} ( - 1 - 3 i )}{2 \cdot 3}

취소하다 :

\frac{- 1 - 3 i}{2 \cdot 3 ^{\frac{1}{3}}}

\frac{3 ^{\frac{2}{3}} ( - 1 - 3 i )}{2 \cdot 3}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{2}{3}}}{3} = \frac{1}{3 ^{1 - \frac{2}{3}}}

= \frac{- 1 - 3 i}{2 \cdot 3 ^{- \frac{2}{3} + 1}}

숫자를 빼세요:

1 - \frac{2}{3} = \frac{1}{3}

= \frac{- 1 - 3 i}{2 \cdot 3 ^{\frac{1}{3}}}

= \frac{- 1 - 3 i}{2 \cdot 3 ^{\frac{1}{3}}}

3^{\frac{1}{3}} = 33

급진적인 규칙 적용:

a^{\frac{1}{n}} = n a

3^{\frac{1}{3}} = 33

= \frac{- 1 - 3 i}{2 3 3}

분수 규칙 적용:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 1 - 3 i}{2 3 3} = - \frac{1}{2 3 3} - \frac{3 i}{2 3 3}

= - \frac{1}{2 3 3} - \frac{3 i}{2 3 3}

\frac{3 i}{2 3 3}

취소하다 :

\frac{6 3 i}{2}

\frac{3 i}{2 3 3}

\frac{3 i}{2 3 3}

취소하다 :

\frac{6 3 i}{2}

\frac{3 i}{2 3 3}

급진적인 규칙 적용:

n a = a^{\frac{1}{n}}

33 = 3^{\frac{1}{3}}, 3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}} i}{2 \cdot 3 ^{\frac{1}{3}}}

지수 규칙 적용:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{3 ^{\frac{1}{2}}}{3 ^{\frac{1}{3}}} = 3^{\frac{1}{2} - \frac{1}{3}}

= \frac{3 ^{\frac{1}{2} - \frac{1}{3}} i}{2}

숫자를 빼세요:

\frac{1}{2} - \frac{1}{3} = \frac{1}{6}

= \frac{3 ^{\frac{1}{6}} i}{2}

급진적인 규칙 적용:

a^{\frac{1}{n}} = n a

3^{\frac{1}{6}} = 63

= \frac{6 3 i}{2}

= \frac{6 3 i}{2}

= - \frac{1}{2 3 3} - \frac{6 3 i}{2}

- \frac{1}{2 3 3} = - \frac{3 ^{\frac{2}{3}}}{6}

- \frac{1}{2 3 3}

공역에 곱셈

\frac{3 ^{\frac{2}{3}}}{3 ^{\frac{2}{3}}}

= - \frac{1 \cdot 3 ^{\frac{2}{3}}}{2 3 3 \cdot 3 ^{\frac{2}{3}}}

1 \cdot 3^{\frac{2}{3}} = 3^{\frac{2}{3}}

233 \cdot 3^{\frac{2}{3}} = 6

233 \cdot 3^{\frac{2}{3}}

지수 규칙 적용:

a^{b} \cdot a^{c} = a^{b + c}

3^{\frac{2}{3}} 33 = 3^{\frac{2}{3}} \cdot 3^{\frac{1}{3}} = 3^{\frac{2}{3} + \frac{1}{3}}

= 2 \cdot 3^{\frac{2}{3} + \frac{1}{3}}

3^{\frac{2}{3} + \frac{1}{3}} = 3

3^{\frac{2}{3} + \frac{1}{3}}

분수를 합치다

\frac{2}{3} + \frac{1}{3} : 1

규칙 적용

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

숫자 추가:

2 + 1 = 3

= \frac{3}{3}

규칙 적용

\frac{a}{a} = 1

= 1

= 3^{1}

규칙 적용

a^{1} = a

= 3

= 2 \cdot 3

숫자를 곱하시오:

2 \cdot 3 = 6

= 6

= - \frac{3 ^{\frac{2}{3}}}{6}

= - \frac{3 ^{\frac{2}{3}}}{6} - \frac{6 3}{2} i

= - \frac{3 ^{\frac{2}{3}}}{6} - \frac{6 3}{2} i

u = 3 \frac{1}{3}, u = - \frac{3 ^{\frac{2}{3}}}{6} + i \frac{6 3}{2}, u = - \frac{3 ^{\frac{2}{3}}}{6} - i \frac{6 3}{2}

뒤로 대체

u = tan (x)

tan (x) = 3 \frac{1}{3}, tan (x) = - \frac{3 ^{\frac{2}{3}}}{6} + i \frac{6 3}{2}, tan (x) = - \frac{3 ^{\frac{2}{3}}}{6} - i \frac{6 3}{2}

tan (x) = 3 \frac{1}{3}, tan (x) = - \frac{3 ^{\frac{2}{3}}}{6} + i \frac{6 3}{2}, tan (x) = - \frac{3 ^{\frac{2}{3}}}{6} - i \frac{6 3}{2}

tan (x) = 3 \frac{1}{3} : x = arctan (3 \frac{1}{3}) + πn

tan (x) = 3 \frac{1}{3}

트리거 역속성 적용

tan (x) = 3 \frac{1}{3}

일반 솔루션

tan (x) = 3 \frac{1}{3}

tan (x) = a \Rightarrow x = arctan (a) + πn

x = arctan (3 \frac{1}{3}) + πn

x = arctan (3 \frac{1}{3}) + πn

tan (x) = - \frac{3 ^{\frac{2}{3}}}{6} + i \frac{6 3}{2} :

해결책 없음

tan (x) = - \frac{3 ^{\frac{2}{3}}}{6} + i \frac{6 3}{2}

해결책 없음

tan (x) = - \frac{3 ^{\frac{2}{3}}}{6} - i \frac{6 3}{2} :

해결책 없음

tan (x) = - \frac{3 ^{\frac{2}{3}}}{6} - i \frac{6 3}{2}

해결책 없음

모든 솔루션 결합

x = arctan (3 \frac{1}{3}) + πn

해를 10진수 형식으로 표시

x = 0.60625 \dots + πn

그래프

인기 있는 예

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