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Beliebt Trigonometrie >

sin(x)= 4/5 ,0<= x<2pi

Lösung

sin (x) = \frac{4}{5}, 0 \leq x < 2 π

Lösung

x = 0.92729 \dots, x = π - 0.92729 \dots

+1

Grad

x = 53.13010 \dots^{\circ}, x = 126.86989 \dots^{\circ}

Schritte zur Lösung

sin (x) = \frac{4}{5}, 0 \leq x < 2 π

Wende die Eigenschaften der Trigonometrie an

sin (x) = \frac{4}{5}

Allgemeine Lösung für

sin (x) = \frac{4}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{4}{5}) + 2 πn, x = π - arcsin (\frac{4}{5}) + 2 πn

x = arcsin (\frac{4}{5}) + 2 πn, x = π - arcsin (\frac{4}{5}) + 2 πn

Lösungen für den Bereich

0 \leq x < 2 π

x = arcsin (\frac{4}{5}), x = π - arcsin (\frac{4}{5})

Zeige Lösungen in Dezimalform

x = 0.92729 \dots, x = π - 0.92729 \dots

Graph

Beliebte Beispiele

7sin^2(θ)-5sin(θ)=2

7 sin^{2} (θ) - 5 sin (θ) = 2

sec(2x)=-(2/(sqrt(3)))

sec (2 x) = - (\frac{2}{3})

(e^{-ln(-(sin(θ))/(cos(θ)))})/2*sin(θ)=0

\frac{e ^{- l n (- \frac{s i n ( θ )}{c o s ( θ )})}}{2} \cdot sin (θ) = 0

7sin(2x)+12sin(x)=0

7 sin (2 x) + 12 sin (x) = 0

solvefor x,cos(x)=cos(2x)

so l v e f or x, cos (x) = cos (2 x)