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受欢迎的三角函数 >

cos(W)=(170^2+173^2-125^2)/(2(170)(173))

解答

cos (W) = \frac{17 0 ^{2} + 17 3 ^{2} - 12 5 ^{2}}{2 ( 170 ) ( 173 )}

解答

W = 0.74584 \dots + 2 πn, W = 2 π - 0.74584 \dots + 2 πn

+1

弧度

W = 0.74584 \dots + 6.28318 \dots n, W = 5.53733 \dots + 6.28318 \dots n

求解步骤

cos (W) = \frac{17 0 ^{2} + 17 3 ^{2} - 12 5 ^{2}}{2 ( 170 ) ( 173 )}

化简

\frac{17 0 ^{2} + 17 3 ^{2} - 12 5 ^{2}}{2 \cdot 170 \cdot 173} : \frac{10801}{14705}

\frac{17 0 ^{2} + 17 3 ^{2} - 12 5 ^{2}}{2 \cdot 170 \cdot 173}

17 0^{2} + 17 3^{2} - 12 5^{2} = 43204

17 0^{2} + 17 3^{2} - 12 5^{2}

17 0^{2} = 28900

= 28900 + 17 3^{2} - 12 5^{2}

17 3^{2} = 29929

= 28900 + 29929 - 12 5^{2}

12 5^{2} = 15625

= 28900 + 29929 - 15625

数字相加/相减:

28900 + 29929 - 15625 = 43204

= 43204

= \frac{43204}{2 \cdot 170 \cdot 173}

数字相乘:

2 \cdot 170 \cdot 173 = 58820

= \frac{43204}{58820}

约分:

4

= \frac{10801}{14705}

使用反三角函数性质

cos (W) = \frac{10801}{14705}

cos (W) = \frac{10801}{14705}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

W = arccos (\frac{10801}{14705}) + 2 πn, W = 2 π - arccos (\frac{10801}{14705}) + 2 πn

W = arccos (\frac{10801}{14705}) + 2 πn, W = 2 π - arccos (\frac{10801}{14705}) + 2 πn

以小数形式表示解

W = 0.74584 \dots + 2 πn, W = 2 π - 0.74584 \dots + 2 πn

作图

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