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人気のある三角関数 >

(sin(95))/(27)=(sin(b))/(16)

解

\frac{sin ( 9 5 ^{\circ} )}{27} = \frac{sin ( b )}{16}

解

b = 0.63147 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.63147 \dots + 36 0^{\circ} n

+1

ラジアン

b = 0.63147 \dots + 2 πn, b = π - 0.63147 \dots + 2 πn

解答ステップ

\frac{sin ( 9 5 ^{\circ} )}{27} = \frac{sin ( b )}{16}

辺を交換する

\frac{sin ( b )}{16} = \frac{sin ( 9 5 ^{\circ} )}{27}

以下で両辺を乗じる:

16

\frac{sin ( b )}{16} = \frac{sin ( 9 5 ^{\circ} )}{27}

以下で両辺を乗じる:

16

\frac{16 sin ( b )}{16} = \frac{16 sin ( 9 5 ^{\circ} )}{27}

簡素化

sin (b) = \frac{16 sin ( 9 5 ^{\circ} )}{27}

sin (b) = \frac{16 sin ( 9 5 ^{\circ} )}{27}

三角関数の逆数プロパティを適用する

sin (b) = \frac{16 sin ( 9 5 ^{\circ} )}{27}

以下の一般解

sin (b) = \frac{16 sin ( 9 5 ^{\circ} )}{27}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{16 sin ( 9 5 ^{\circ} )}{27}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{16 sin ( 9 5 ^{\circ} )}{27}) + 36 0^{\circ} n

b = arcsin (\frac{16 sin ( 9 5 ^{\circ} )}{27}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{16 sin ( 9 5 ^{\circ} )}{27}) + 36 0^{\circ} n

10進法形式で解を証明する

b = 0.63147 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.63147 \dots + 36 0^{\circ} n

グラフ

人気の例

sec(θ)=-7/(sqrt(13))

sec (θ) = - \frac{7}{13}

tan(x)=-infinity

tan (x) = - \infty

tan(2x)+tan(4x)=0

tan (2 x) + tan (4 x) = 0

tan^2(θ)-tan(θ)-2=0

tan^{2} (θ) - tan (θ) - 2 = 0

cos (a) = 0.94