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受欢迎的三角函数 >

sqrt(2/(pi0.5)tan((pi0.5)/2))

解答

\frac{2}{π \cdot 0.5} tan (\frac{π \cdot 0.5}{2})

解答

\frac{2 π}{π}

+1

十进制

1.12837 \dots

求解步骤

\frac{2}{π 0.5} tan (\frac{π 0.5}{2})

= \frac{2}{π \frac{1}{2}} tan (\frac{π \frac{1}{2}}{2})

化简:

\frac{π \frac{1}{2}}{2} = \frac{π}{4}

\frac{π \frac{1}{2}}{2}

乘

π \frac{1}{2} : \frac{π}{2}

π \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 π}{2}

乘以:

1 π = π

= \frac{π}{2}

= \frac{\frac{π}{2}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{π}{4}

\frac{2}{π \frac{1}{2}} tan (\frac{π}{4}) = \frac{2 π tan ( \frac{π}{4} )}{π}

\frac{2}{π \frac{1}{2}} tan (\frac{π}{4})

乘

\frac{2}{π \frac{1}{2}} tan (\frac{π}{4}) : \frac{4 tan ( \frac{π}{4} )}{π}

\frac{2}{π \frac{1}{2}} tan (\frac{π}{4})

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 tan ( \frac{π}{4} )}{π \frac{1}{2}}

乘

π \frac{1}{2} : \frac{π}{2}

π \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 π}{2}

乘以:

1 π = π

= \frac{π}{2}

= \frac{2 tan ( \frac{π}{4} )}{\frac{π}{2}}

使用分式法则:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{2 tan ( \frac{π}{4} ) \cdot 2}{π}

数字相乘:

2 \cdot 2 = 4

= \frac{4 tan ( \frac{π}{4} )}{π}

= \frac{4 tan ( \frac{π}{4} )}{π}

使用根式运算法则:

n \frac{a}{b} = \frac{n a}{n b},

假定

a \geq 0, b \geq 0

= \frac{4 tan ( \frac{π}{4} )}{π}

使用根式运算法则:

n ab = n a n b,

假定

a \geq 0, b \geq 0

4 tan (\frac{π}{4}) = 4 tan (\frac{π}{4})

= \frac{4 tan ( \frac{π}{4} )}{π}

4 = 2

4

因式分解数字:

4 = 2^{2}

= 2^{2}

使用根式运算法则:

n a^{n} = a

2^{2} = 2

= 2

= \frac{2 tan ( \frac{π}{4} )}{π}

\frac{2 tan ( \frac{π}{4} )}{π}

有理化:

\frac{2 π tan ( \frac{π}{4} )}{π}

\frac{2 tan ( \frac{π}{4} )}{π}

乘以共轭根式

\frac{π}{π}

= \frac{2 tan ( \frac{π}{4} ) π}{π π}

π π = π

π π

使用根式运算法则:

a a = a

π π = π

= π

= \frac{2 π tan ( \frac{π}{4} )}{π}

= \frac{2 π tan ( \frac{π}{4} )}{π}

= \frac{2 π tan ( \frac{π}{4} )}{π}

使用以下普通恒等式:

tan (\frac{π}{4}) = 1

tan (\frac{π}{4})

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 1

= \frac{2 π 1}{π}

化简

= \frac{2 π}{π}

流行的例子

sqrt(3[cos((4pi)/9)+isin((4pi)/9)])

3 [cos (\frac{4 π}{9}) + i sin (\frac{4 π}{9})]

cos (\frac{61 π}{4})

cot (0.785)

sin (4 2^{\circ}) \cdot 4.6

csc (- 148 5^{\circ})