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人気のある三角関数 >

4cos^2(60)+4sin^2(45)-sin^2(30)

解

4 cos^{2} (6 0^{\circ}) + 4 sin^{2} (4 5^{\circ}) - sin^{2} (3 0^{\circ})

解

\frac{11}{4}

+1

十進法表記

2.75

解答ステップ

4 cos^{2} (6 0^{\circ}) + 4 sin^{2} (4 5^{\circ}) - sin^{2} (3 0^{\circ})

次の自明恒等式を使用する:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

36 0^{\circ} n

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

次の自明恒等式を使用する:

sin (4 5^{\circ}) = \frac{2}{2}

sin (4 5^{\circ})

sin (x)

36 0^{\circ} n

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

次の自明恒等式を使用する:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

36 0^{\circ} n

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= 4 (\frac{1}{2})^{2} + 4 (\frac{2}{2})^{2} - (\frac{1}{2})^{2}

簡素化

4 (\frac{1}{2})^{2} + 4 (\frac{2}{2})^{2} - (\frac{1}{2})^{2} : \frac{11}{4}

4 (\frac{1}{2})^{2} + 4 (\frac{2}{2})^{2} - (\frac{1}{2})^{2}

条件のようなグループ

= 4 (\frac{1}{2})^{2} - (\frac{1}{2})^{2} + 4 (\frac{2}{2})^{2}

類似した元を足す:

4 (\frac{1}{2})^{2} - (\frac{1}{2})^{2} = 3 (\frac{1}{2})^{2}

= 3 (\frac{1}{2})^{2} + 4 (\frac{2}{2})^{2}

3 (\frac{1}{2})^{2} = \frac{3}{4}

3 (\frac{1}{2})^{2}

(\frac{1}{2})^{2} = \frac{1}{2 ^{2}}

(\frac{1}{2})^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

規則を適用

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

= 3 \cdot \frac{1}{2 ^{2}}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 3}{2 ^{2}}

数を乗じる:

1 \cdot 3 = 3

= \frac{3}{2 ^{2}}

2^{2} = 4

= \frac{3}{4}

4 (\frac{2}{2})^{2} = 2

4 (\frac{2}{2})^{2}

(\frac{2}{2})^{2} = \frac{1}{2}

(\frac{2}{2})^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 ) ^{2}}{2 ^{2}}

(2)^{2} : 2

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= (2^{\frac{1}{2}})^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= 2^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 2

= \frac{2}{2 ^{2}}

共通因数を約分する:

2

= \frac{1}{2}

= 4 \cdot \frac{1}{2}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 4}{2}

数を乗じる:

1 \cdot 4 = 4

= \frac{4}{2}

数を割る:

\frac{4}{2} = 2

= 2

= \frac{3}{4} + 2

元を分数に変換する:

2 = \frac{2 \cdot 4}{4}

= \frac{2 \cdot 4}{4} + \frac{3}{4}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 4 + 3}{4}

2 \cdot 4 + 3 = 11

2 \cdot 4 + 3

数を乗じる:

2 \cdot 4 = 8

= 8 + 3

数を足す:

8 + 3 = 11

= 11

= \frac{11}{4}

= \frac{11}{4}

人気の例

sin((3pi)/(18))

sin (\frac{3 π}{18})

arccos (\frac{7}{15})

tan (- \frac{29 π}{3})

arcsin (0.11)

(sin(43.5))/(1.56)

\frac{sin ( 43. 5 ^{\circ} )}{1.56}