beweisen 1+tan^2(30)=sec^2(30)

Lösung

beweisen

1 + tan^{2} (3 0^{\circ}) = sec^{2} (3 0^{\circ})

Wahr

Schritte zur Lösung

1 + tan^{2} (3 0^{\circ}) = sec^{2} (3 0^{\circ})

Verwende die Pythagoreische Identität:

tan^{2} (x) + 1 = sec^{2} (x)

\Rightarrow Wahr

p ro v e \frac{cos ( θ )}{1 - sin ( θ )} - tan (θ) = sec (θ)

p ro v e sin^{2} (θ) sec (θ) csc (θ) = tan (θ)

p ro v e csc (x) (cos (x) + sin (x)) = cot (x) + 1

p ro v e cos^{2} (x) + cos^{2} (x) cot^{2} (x) = cot^{2} (x)

p ro v e 2 cos (x - \frac{π}{4}) = cos (x) + sin (x)