sin(θ)= 4/5 ,0<θ< pi/2 ,sin(2θ)

Lösung

sin (θ) = \frac{4}{5}, 0 < θ < \frac{π}{2}, sin (2 θ)

θ = 0.92729 \dots

Grad

θ = 53.13010 \dots^{\circ}

Schritte zur Lösung

sin (θ) = \frac{4}{5}, 0 < θ < \frac{π}{2}, sin (2 θ)

Wende die Eigenschaften der Trigonometrie an

sin (θ) = \frac{4}{5}

Allgemeine Lösung für

sin (θ) = \frac{4}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

θ = arcsin (\frac{4}{5}) + 2 πn, θ = π - arcsin (\frac{4}{5}) + 2 πn

Lösungen für den Bereich

0 < θ < \frac{π}{2}

θ = arcsin (\frac{4}{5})

Zeige Lösungen in Dezimalform

θ = 0.92729 \dots

sin (x) - 4 = cos (x) - 4

cos (9 x + 15) = sin (7 x - 5)

3 cos (2 θ) - sin (θ) = 1

sin (t) + 2 = 3

2 sech^{2} (x) + tanh (x) = 0