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受欢迎的三角函数 >

solvefor t,x=4cos(t)

解答

求解

t, x = 4 cos (t)

解答

t = arccos (\frac{x}{4}) + 2 πn, t = - arccos (\frac{x}{4}) + 2 πn

求解步骤

x = 4 cos (t)

交换两边

4 cos (t) = x

两边除以

4

4 cos (t) = x

两边除以

4

\frac{4 cos ( t )}{4} = \frac{x}{4}

化简

cos (t) = \frac{x}{4}

cos (t) = \frac{x}{4}

使用反三角函数性质

cos (t) = \frac{x}{4}

cos (t) = \frac{x}{4}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

t = arccos (\frac{x}{4}) + 2 πn, t = - arccos (\frac{x}{4}) + 2 πn

t = arccos (\frac{x}{4}) + 2 πn, t = - arccos (\frac{x}{4}) + 2 πn

作图

流行的例子

2cos^3(θ)-cos(θ)=0

2 cos^{3} (θ) - cos (θ) = 0

- sin (π x) π = 0

cos^2(x)-3sin^2(x)=1

cos^{2} (x) - 3 sin^{2} (x) = 1

sin (\frac{x}{6}) = 0

(tan(θ)-1)(sec(θ)-1)=0,0<= θ<= 2pi

(tan (θ) - 1) (sec (θ) - 1) = 0, 0 \leq θ \leq 2 π