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受欢迎的初等代数 >

1/7 × (3+1 1/5)

解答

\frac{1}{7} \cdot (3 + 1 \frac{1}{5})

解答

\frac{3}{5}

+1

十进制

0.6

求解步骤

\frac{1}{7} \cdot (3 + 1 \frac{1}{5})

将带分数转换为假分式:

1 \frac{1}{5} = \frac{6}{5}

1 \frac{1}{5}

将带分数转换为假分式:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

1 \frac{1}{5} = \frac{1 \cdot 5 + 1}{5}

= \frac{6}{5}

= \frac{1}{7} \cdot (3 + \frac{6}{5})

遵循 PEMDAS 运算顺序

计算括号内的值

(3 + \frac{6}{5}) : \frac{21}{5}

3 + \frac{6}{5}

3 + \frac{6}{5} = \frac{21}{5}

3 + \frac{6}{5}

将项转换为分式:

3 = \frac{3 \cdot 5}{5}

= \frac{3 \cdot 5}{5} + \frac{6}{5}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 5 + 6}{5}

3 \cdot 5 + 6 = 21

3 \cdot 5 + 6

数字相乘:

3 \cdot 5 = 15

= 15 + 6

数字相加:

15 + 6 = 21

= 21

= \frac{21}{5}

= \frac{21}{5}

= \frac{1}{7} \cdot \frac{21}{5}

乘除（左右）

\frac{1}{7} \cdot \frac{21}{5} : \frac{3}{5}

\frac{1}{7} \cdot \frac{21}{5}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 21}{7 \cdot 5}

\frac{1 \cdot 21}{7 \cdot 5} = \frac{3}{5}

\frac{1 \cdot 21}{7 \cdot 5}

数字相乘:

1 \cdot 21 = 21

= \frac{21}{7 \cdot 5}

因式分解数字:

21 = 7 \cdot 3

= \frac{7 \cdot 3}{7 \cdot 5}

约分:

7

= \frac{3}{5}

= \frac{3}{5}

= \frac{3}{5}

流行的例子

- (- 2)^{2} - 1

2(2)^2+1(2)+(2(4)-4)

2 (2)^{2} + 1 (2) + (2 (4) - 4)

5 (12) + 3

5 \times (- 2) - 2

9 - (16 + 25)