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受欢迎的初等代数 >

(5/3-1)*(7/2-2)

解答

(\frac{5}{3} - 1) \cdot (\frac{7}{2} - 2)

解答

1

求解步骤

(\frac{5}{3} - 1) (\frac{7}{2} - 2)

遵循 PEMDAS 运算顺序

计算括号内的值

(\frac{5}{3} - 1) : \frac{2}{3}

\frac{5}{3} - 1

\frac{5}{3} - 1 = \frac{2}{3}

\frac{5}{3} - 1

将项转换为分式:

1 = \frac{1 \cdot 3}{3}

= - \frac{1 \cdot 3}{3} + \frac{5}{3}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 3 + 5}{3}

- 1 \cdot 3 + 5 = 2

- 1 \cdot 3 + 5

数字相乘:

1 \cdot 3 = 3

= - 3 + 5

数字相加/相减:

- 3 + 5 = 2

= 2

= \frac{2}{3}

= \frac{2}{3}

= \frac{2}{3} (\frac{7}{2} - 2)

计算括号内的值

(\frac{7}{2} - 2) : \frac{3}{2}

\frac{7}{2} - 2

\frac{7}{2} - 2 = \frac{3}{2}

\frac{7}{2} - 2

将项转换为分式:

2 = \frac{2 \cdot 2}{2}

= - \frac{2 \cdot 2}{2} + \frac{7}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 2 \cdot 2 + 7}{2}

- 2 \cdot 2 + 7 = 3

- 2 \cdot 2 + 7

数字相乘:

2 \cdot 2 = 4

= - 4 + 7

数字相加/相减:

- 4 + 7 = 3

= 3

= \frac{3}{2}

= \frac{3}{2}

= \frac{2}{3} \cdot \frac{3}{2}

乘除（左右）

\frac{2}{3} \cdot \frac{3}{2} : 1

\frac{2}{3} \cdot \frac{3}{2}

\frac{2}{3} \cdot \frac{3}{2} = 1

= 1

= 1

流行的例子

3 + 3 (6 + 1)

4 \cdot 1 0^{2}

- 4 + 8 - 5

2 \times 2 + 1

0 - 1 + 1 - 1