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Beliebt Geometry >

leitkurve y+8x^2=0

Lösung

leitkurve

y + 8 x^{2} = 0

Lösung

y = \frac{1}{32}

Schritte zur Lösung

Rewrite

y + 8 x^{2} = 0

in the standard form:

4 (- \frac{1}{32}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{32}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{32})

Fasse zusammen

y = \frac{1}{32}

Graph

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