leitkurve y=(95x^2-10x+26)/(10)

Lösung

leitkurve

y = \frac{95 x ^{2} - 10 x + 26}{10}

y = \frac{242}{95}

Schritte zur Lösung

Rewrite

y = \frac{95 x ^{2} - 10 x + 26}{10}

in the standard form

4 \cdot \frac{1}{38} (y - \frac{489}{190}) = (x - \frac{1}{19})^{2}

(h, k) = (\frac{1}{19}, \frac{489}{190}), p = \frac{1}{38}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{1}{19}, \frac{489}{190})

y-coordinate

y = \frac{489}{190} - p

y = \frac{489}{190} - \frac{1}{38}

Fasse zusammen

y = \frac{242}{95}

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d i rec t r i x \frac{1}{8} x^{2}

d i rec t r i x x^{2} + 8 x - 4 y - 36 = 0

d i rec t r i x \frac{1}{400} x^{2} - x + 150