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Beliebt Geometry >

leitkurve y^2-16x=0

Lösung

leitkurve

y^{2} - 16 x = 0

Lösung

x = - 4

Schritte zur Lösung

Rewrite

y^{2} - 16 x = 0

in the standard form:

4 \cdot 4 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 4

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 4

Fasse zusammen

x = - 4

Graph

Beliebte Beispiele

leitkurve 2x^2-8x+9

d i rec t r i x 2 x^{2} - 8 x + 9

leitkurve y=(x^2-4x-1)/7

d i rec t r i x y = \frac{x ^{2} - 4 x - 1}{7}

leitkurve y^2-28x=0

d i rec t r i x y^{2} - 28 x = 0

leitkurve 3y^2=-4x

d i rec t r i x 3 y^{2} = - 4 x

leitkurve y=-x^2+6x

d i rec t r i x y = - x^{2} + 6 x