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Beliebt Geometry >

leitkurve x=2y^2-1-(5y-6)

Lösung

leitkurve

x = 2 y^{2} - 1 - (5 y - 6)

Lösung

x = \frac{7}{4}

Schritte zur Lösung

Rewrite

x = 2 y^{2} - 1 - (5 y - 6)

in the standard form

4 \cdot \frac{1}{8} (x - \frac{15}{8}) = (y - \frac{5}{4})^{2}

(h, k) = (\frac{15}{8}, \frac{5}{4}), p = \frac{1}{8}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(\frac{15}{8}, \frac{5}{4})

x-coordinate

x = \frac{15}{8} - p

x = \frac{15}{8} - \frac{1}{8}

Fasse zusammen

x = \frac{7}{4}

Graph

Beliebte Beispiele

leitkurve x^2-2x-4y+13=0

d i rec t r i x x^{2} - 2 x - 4 y + 13 = 0

leitkurve y=18x^2-14x+9

d i rec t r i x y = 18 x^{2} - 14 x + 9

leitkurve y=+x^2-3

d i rec t r i x y = + x^{2} - 3

leitkurve x^2-26x+65

d i rec t r i x x^{2} - 26 x + 65

leitkurve y^2-4x+4y-4=0

d i rec t r i x y^{2} - 4 x + 4 y - 4 = 0