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Beliebt Geometry >

center x^2+y^2+8x+4y-3=40

Lösung

center

x^{2} + y^{2} + 8 x + 4 y - 3 = 40

Lösung

(- 4, - 2)

Schritte zur Lösung

x^{2} + y^{2} + 8 x + 4 y - 3 = 40

Rewrite

x^{2} + y^{2} + 8 x + 4 y - 3 = 40

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 2))^{2} = (37)^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 2), r = 37

And the center is:

(- 4, - 2)

Graph

Beliebte Beispiele

(x-1)^2=-4(y-2)

(x - 1)^{2} = - 4 (y - 2)

foki (x^2}{16}-\frac{y^2)/4 =1

f oc i \frac{x ^{2}}{16} - \frac{y ^{2}}{4} = 1

foki x^2+(y^2)/(49)=1

f oc i x^{2} + \frac{y ^{2}}{49} = 1

(x^2)/4-(y^2)/(25)=1

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

scheitelpunkte y^2=16x

v er t i ces y^{2} = 16 x