de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

foki x=-1/2 (y-2)^2+5

Lösung

foki

x = - \frac{1}{2} (y - 2)^{2} + 5

Lösung

(\frac{9}{2}, 2)

Schritte zur Lösung

Rewrite

x = - \frac{1}{2} (y - 2)^{2} + 5

in the standard form:

4 (- \frac{1}{2}) (x - 5) = (y - 2)^{2}

(h, k) = (5, 2), p = - \frac{1}{2}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(5, 2)

along the x-axis

(5 + p, 2)

= (5 + (- \frac{1}{2}), 2)

Fasse zusammen

(\frac{9}{2}, 2)

Graph

Beliebte Beispiele

f oc i (2 + x)^{2}

foki (40x^3)/(3x)

f oc i \frac{40 x ^{3}}{3 x}

f oc i y = 10 x - x^{2}

foki y=(6x+7)^2

f oc i y = (6 x + 7)^{2}

foki (x^2)/(16)

f oc i \frac{x ^{2}}{16}