de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

foki y=p(x-h)^2+k

Lösung

foki

y = p (x - h)^{2} + k

Lösung

(h, \frac{4 p k + 1}{4 p})

Schritte zur Lösung

Rewrite

y = p (x - h)^{2} + k

in the standard form:

4 \cdot \frac{1}{4 p} (y - k) = (x - h)^{2}

(h, k) = (h, k), p = \frac{1}{4 p}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(h, k)

along the y-axis

(h, k + p)

= (h, k + \frac{1}{4 p})

Fasse zusammen

(h, \frac{4 p k + 1}{4 p})

Beliebte Beispiele

foki (x-3)^2=-12y

f oc i (x - 3)^{2} = - 12 y

f oc i y = 3 x^{2} + 6

f oc i y = 2 x^{2} - x

foki x=-1/12 (y+10)^2-6

f oc i x = - \frac{1}{12} (y + 10)^{2} - 6

f oc i y = 2 x^{2} - 9