de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

foki y=6x^2-29x-5

Lösung

foki

y = 6 x^{2} - 29 x - 5

Lösung

(\frac{29}{12}, - 40)

Schritte zur Lösung

Rewrite

y = 6 x^{2} - 29 x - 5

in the standard form

4 \cdot \frac{1}{24} (y - (- \frac{961}{24})) = (x - \frac{29}{12})^{2}

(h, k) = (\frac{29}{12}, - \frac{961}{24}), p = \frac{1}{24}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{29}{12}, - \frac{961}{24})

along the y-axis

(\frac{29}{12}, - \frac{961}{24} + p)

= (\frac{29}{12}, - \frac{961}{24} + \frac{1}{24})

Fasse zusammen

(\frac{29}{12}, - 40)

Graph

Beliebte Beispiele

foki y=1-3x-x^2

f oc i y = 1 - 3 x - x^{2}

foki x^2-2x-4y+13=0

f oc i x^{2} - 2 x - 4 y + 13 = 0

foki 2y^2-16y+72=20x

f oc i 2 y^{2} - 16 y + 72 = 20 x

foki y^2+4x-8y+12=0

f oc i y^{2} + 4 x - 8 y + 12 = 0

f oc i - x^{2} + 4 x - 1