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Beliebt Geometry >

foki y^2+8y+4x+20=0

Lösung

foki

y^{2} + 8 y + 4 x + 20 = 0

Lösung

(- 2, - 4)

Schritte zur Lösung

Rewrite

y^{2} + 8 y + 4 x + 20 = 0

in the standard form

4 (- 1) (x - (- 1)) = (y - (- 4))^{2}

(h, k) = (- 1, - 4), p = - 1

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 1, - 4)

along the x-axis

(- 1 + p, - 4)

= (- 1 + (- 1), - 4)

Fasse zusammen

(- 2, - 4)

Graph

Beliebte Beispiele

foki (y+5)^2=-12(x-2)

f oc i (y + 5)^{2} = - 12 (x - 2)

f oc i y = 4 x - x^{2}

foki y^2-12x-2y+25=0

f oc i y^{2} - 12 x - 2 y + 25 = 0

f oc i - x^{2} + 4 x + 5

f oc i x = - 3 y^{2}