de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

foki y=(2x-1)(4x-1)

Lösung

foki

y = (2 x - 1) (4 x - 1)

Lösung

(\frac{3}{8}, - \frac{3}{32})

Schritte zur Lösung

Rewrite

y = (2 x - 1) (4 x - 1)

in the standard form

4 \cdot \frac{1}{32} (y - (- \frac{1}{8})) = (x - \frac{3}{8})^{2}

(h, k) = (\frac{3}{8}, - \frac{1}{8}), p = \frac{1}{32}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{3}{8}, - \frac{1}{8})

along the y-axis

(\frac{3}{8}, - \frac{1}{8} + p)

= (\frac{3}{8}, - \frac{1}{8} + \frac{1}{32})

Fasse zusammen

(\frac{3}{8}, - \frac{3}{32})

Graph

Beliebte Beispiele

foki (y+6)^2=12(x+1)

f oc i (y + 6)^{2} = 12 (x + 1)

foki (x+7)^2=5(y+3)

f oc i (x + 7)^{2} = 5 (y + 3)

f oc i x^{2} - 8 y = 0

foki (x+3)^2=-y

f oc i (x + 3)^{2} = - y

foki-(x^2)/8+x/4+23/8

f oc i - \frac{x ^{2}}{8} + \frac{x}{4} + \frac{23}{8}